x^2+(10^-8*)x-(10^-14)=0

Solution for x^2+(10^-8*)x-(10^-14)=0 equation:

x^2+(10^-8*)x-(10^-14)=0

We add all the numbers together, and all the variables

x^2+(10^-8*)x-14-1.0E=0

We multiply parentheses

x^2+10x^2-8x^2-14-1.0E=0

We add all the numbers together, and all the variables

3x^2-16.718281828459=0

a = 3; b = 0; c = -16.718281828459;
Δ = b2-4ac
Δ = 02-4·3·(-16.718281828459)
Δ = 200.61938194151
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{200.61938194151}}{2*3}=\frac{0-\sqrt{200.61938194151}}{6}
=-\frac{\sqrt{}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{200.61938194151}}{2*3}=\frac{0+\sqrt{200.61938194151}}{6}
=\frac{\sqrt{}}{6}
$